CLASS 1X-CHEMISTRY
SAMPLE PAPER WITH SOLUTIONS
1. Q. Write the charge and mass of. an electron
SAMPLE PAPER WITH SOLUTIONS
1. Q. Write the charge and mass of. an electron
2. Q. List three subatomic
particles of an atom. Compare them on the basis of relative mass and charge in
a tabular form.
3. Q. Find the number of electrons,
protons and neutron possessed by the alpha particles used in the gold
leaf experiment.
4. Q. Draw Bohr’s model for an
atom with
(i) valency =
1, (ii) number of orbits =
3 (iii) mass number =23.
Also identify the element. What
conclusion can be drawn about the reactivity of the element?
5. Q. (a) You are given an element.
Find out
(i) Number of protons, electrons and
neutrons in ‘X’. (ii) Valency of ‘X’.
(iii) Electronic Configuration of
‘X’.
(b) If bromine atom is
available in the form of, say two isotopes 35 (49.7%) and (50.3%).Calculate the
average atomic mass of bromine atom.
6. Q. (a) From Rutherford’s a -
particle scattering experiment give the experimental evidence for deriving the
conclusion that
(i) Most of the space inside the
atom is empty.
(ii) Whole mass of an atom is
concentrated in its centre.
(iii) The nucleus of an atom is
positively charged.
(b) An element has mass number 31
and atomic number 15 find :
(i) the number of neutrons in the
element, and
(ii) the number of electrons in the
outermost shell.
7. Q. Give reasons:
(a) Mass number of an atom excludes
the mass of an electron.
(b) Nucleus of an atom is charged.
(c) Alpha particle scattering
experiment was possible by using gold foil only and not by foil of
any other metal.
8. Q. Laws of conservation of mass
is not fully applicable for: (a)Precipitation reaction
(b) Redox reaction
(c) Nuclear reaction
(d) Displacement
reaction
9. Q. (a) Define the following terms
with one example each. (i) Isotope (ii) Isobar
(b) Name the elements whose isotopes
are used in:
(i) Nuclear Reactor (ii) treatment
of cancer. (iii) Treatment of cancer
10.Q.
State the problem of atomic structure which was solved after the discovery of
neutron.
11.Q. (a) How many electrons are
present in the valence shell of nitrogen, oxygen and argon?
(b) Nucleus of an atom has 5 protons
and 6 neutrons. What is the atomic number, mass number and electronic
configuration of the atom?
12. The description of atomic particles of two elements
X and Y is given below[3]
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(i) What is the atomic number of Y?
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(ii) What is the mass number of X?
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(iii) What is the relation between X and Y?
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(iv) Which element/elements do they represent?
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(v) Write the electronic configuration of X?
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(vi) Write the
cation/anion formed by the element(i) Atomic number of y – 8
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13. Which of the following are isotopes and which are isobars?
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Argon, Protium,
Calcium, Deuterium. Explain why the isotopes have similar chemical properties
but they differ in physical properties?
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14(i) Define mole
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(ii) How is it related to Avogadro constant, relative mass and
molecular mass?
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(iii) What is the number of molecules in 0.25 moles of oxygen
? Avogadro’s no. = 6 .22 x1023.
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OR
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(i) Define atomicity
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(ii) Give an example each of a polyatomic element and a
polyatomic ion.
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(iii) How many atoms are present in CaCl2 molecule and ion? SO4-2
Answers to the
worksheet
Ans:1
Particle Symbol
Charge
Mass
Electron e–
-1.60×10-19 C
9.1×10-31 kg
Ans: 2
.Ans3: The number of electrons,
protons and neutron are 0,2,2
Ans:4 Sodium has 11
protons and 12 neutrons.
So, The mass number is
11 + 12 = 23.
This element is metal
and highly reactive
Ans:5 (i) Number of protons, electrons and
neutrons in ‘X’. are 7, 7 and 7 respectively
(ii) Valency of ‘X’. is = 3 [NH3]
(iii) Electronic Configuration of ‘X’. = 2, 5
(b) The average atomic mass of bromine atom = + = 80u
Ans:6 (a)
(i) Most of the alpha particles passed through gold foil with getting deflected.
(ii) Very few particles were
deflected from their path by 1800 indicating that whole mass of the atom is present in its centre.
(iii) Few particles deflected at
small and large angle from their path indicating that centre is positively
charged
(b) (i) the number of neutrons in the
element = 31-15 = 16
(ii) Electronic configuration 2,8,5 then the number of
electrons in the outermost shell. = 5
ans:7 (a) Mass number is the sum of the number of proton and
neutron present in nucleus of atom therefore Mass number of an atom excludes
the mass of an electron.
(b) Nucleus of an atom is charged as they contain positively
charged proton.
(c) This is because because gold has high malleability and
can be hammered easily into thin sheet. `
(a)Precipitation
reaction (b) Redox reaction
(c) Nuclear reaction
(d) Displacement
reaction
Ans8: (c)
Nuclear reaction
Ans9:(a) Isotopes are defined as the atoms of the same element,
having the same atomic number but different mass numbers.
For example, hydrogen atom, it has three atomic species, namely
Protium, deuterium and tritium. The atomic number of each one is 1, but the
mass number is 1, 2 and 3, respectively.
Other such examples are carbon, C12, C14 and C16 where as chlorine, C35 and Cl37
Isobars. Atoms of different elements with different atomic
numbers, which have the same mass number, are known as isobars. For
example calcium, atomic number 20, and argon, atomic number 18
but the mass number of both these elements is 40.
(b) (i)An isotope of uranium is used as a fuel in nuclear
reactors.
(ii) An isotope of cobalt is used in the treatment of cancer.
(iii) An isotope of iodine is used in the treatment of goitre.
Ans:10- (a) 5, 6 8 electrons are present in the valence shell of nitrogen, oxygen and argon respectively.
(b) Nucleus of an atom has 5 protons and
6 neutrons.
The atomic number = no of proton = 5, mass number = p + n = 5 +
6 = 11
This represents the element Boron
Electronic configuration of the atom of Boron = 2,3
Ans:11 when the neutron was not
discovered, many scientists found that the atomic mass of many atoms was found
to be double or more than double the mass of total number of protons (as the
mass of electron was so small that it was assumed to be negligible), so by the
discovery of neutron led to the solution of this problem. For e.g. the mass of
Carbon 12 atom is 12 u but the no. of protons were 6 so it becomes 6u.
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